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15x^2-5x-7=0
a = 15; b = -5; c = -7;
Δ = b2-4ac
Δ = -52-4·15·(-7)
Δ = 445
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{445}}{2*15}=\frac{5-\sqrt{445}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{445}}{2*15}=\frac{5+\sqrt{445}}{30} $
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